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题目如下
思路如下
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export function findPalindromeNumbers1(max: number): number[] { const res: number[] = [] if (max <= 0) return res
for (let i = 1; i <= max; i++) { const s = i.toString() if (s === s.split('').reverse().join('')) { res.push(i) } }
return res }
export function findPalindromeNumbers2(max: number): number[] { const res: number[] = [] if (max <= 0) return res
for (let i = 1; i <= max; i++) { const s = i.toString() const length = s.length
let flag = true let startIndex = 0 let endIndex = length - 1 while (startIndex < endIndex) { if (s[startIndex] !== s[endIndex]) { flag = false break } else { startIndex++ endIndex-- } }
if (flag) res.push(i) }
return res }
export function findPalindromeNumbers3(max: number): number[] { const res: number[] = [] if (max <= 0) return res
for (let i = 1; i <= max; i++) { let n = i let rev = 0
while (n > 0) { rev = rev * 10 + n % 10 n = Math.floor(n / 10) }
if (i === rev) res.push(i) }
return res }
console.time('findPalindromeNumbers1') findPalindromeNumbers1(100 * 10000) console.timeEnd('findPalindromeNumbers1')
console.time('findPalindromeNumbers2') findPalindromeNumbers2(100 * 10000) console.timeEnd('findPalindromeNumbers2')
console.time('findPalindromeNumbers3') findPalindromeNumbers3(100 * 10000) console.timeEnd('findPalindromeNumbers3')
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单元测试
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import { findPalindromeNumbers1, findPalindromeNumbers2, findPalindromeNumbers3 } from './palindrome-number'
describe('对称数', () => { it('正常情况', () => { const numbers = findPalindromeNumbers3(200) expect(numbers.length).toBe(28) }) it('max 小于等于 0', () => { const numbers = findPalindromeNumbers3(0) expect(numbers).toEqual([]) }) })
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